Base | Representation |
---|---|
bin | 11100001100111011111100… |
… | …111111010100111011110101 |
3 | 121021011120020022212000012210 |
4 | 130030323330333110323311 |
5 | 112224134231332030031 |
6 | 1115444324142004033 |
7 | 35061116554520364 |
oct | 3414737477247365 |
9 | 537146208760183 |
10 | 124034310033141 |
11 | 3658072349a572 |
12 | 11ab281b576619 |
13 | 5429501510661 |
14 | 228b414dd37db |
15 | e5163c801746 |
hex | 70cefcfd4ef5 |
124034310033141 has 4 divisors (see below), whose sum is σ = 165379080044192. Its totient is φ = 82689540022092.
The previous prime is 124034310033077. The next prime is 124034310033157. The reversal of 124034310033141 is 141330013430421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 124034310033141 - 26 = 124034310033077 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 124034310033099 and 124034310033108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124034310033181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20672385005521 + ... + 20672385005526.
It is an arithmetic number, because the mean of its divisors is an integer number (41344770011048).
Almost surely, 2124034310033141 is an apocalyptic number.
It is an amenable number.
124034310033141 is a deficient number, since it is larger than the sum of its proper divisors (41344770011051).
124034310033141 is an equidigital number, since it uses as much as digits as its factorization.
124034310033141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41344770011050.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 124034310033141 its reverse (141330013430421), we get a palindrome (265364323463562).
The spelling of 124034310033141 in words is "one hundred twenty-four trillion, thirty-four billion, three hundred ten million, thirty-three thousand, one hundred forty-one".
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