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12403504441103 = 88713983657769
BaseRepresentation
bin1011010001111110101001…
…1110011110011100001111
31121220202121112212112020012
42310133222132132130033
53111204334114103403
642214031414343435
72420060255120666
oct264375236363417
947822545775205
1012403504441103
113a52329997716
121483a7065ab7b
136bc851090ac9
1430c493377ddd
1516799c301ed8
hexb47ea79e70f

12403504441103 has 4 divisors (see below), whose sum is σ = 12417488099760. Its totient is φ = 12389520782448.

The previous prime is 12403504441091. The next prime is 12403504441109. The reversal of 12403504441103 is 30114440530421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12403504441103 - 210 = 12403504440079 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12403504441103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12403504441109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6991827998 + ... + 6991829771.

It is an arithmetic number, because the mean of its divisors is an integer number (3104372024940).

Almost surely, 212403504441103 is an apocalyptic number.

12403504441103 is a deficient number, since it is larger than the sum of its proper divisors (13983658657).

12403504441103 is an equidigital number, since it uses as much as digits as its factorization.

12403504441103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13983658656.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 12403504441103 its reverse (30114440530421), we get a palindrome (42517944971524).

The spelling of 12403504441103 in words is "twelve trillion, four hundred three billion, five hundred four million, four hundred forty-one thousand, one hundred three".

Divisors: 1 887 13983657769 12403504441103