Base | Representation |
---|---|
bin | 111001110000110001… |
… | …1101100000001100111 |
3 | 102212011210101012120020 |
4 | 1303201203230001213 |
5 | 4013020042011010 |
6 | 132552410410223 |
7 | 11650623523461 |
oct | 1634143540147 |
9 | 385153335506 |
10 | 124043313255 |
11 | 48674242224 |
12 | 20059a30973 |
13 | b90aa92714 |
14 | 600a333131 |
15 | 335ee34470 |
hex | 1ce18ec067 |
124043313255 has 32 divisors (see below), whose sum is σ = 199545016320. Its totient is φ = 65798503680.
The previous prime is 124043313239. The next prime is 124043313263. The reversal of 124043313255 is 552313340421.
It is not a de Polignac number, because 124043313255 - 24 = 124043313239 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3164466 + ... + 3203424.
It is an arithmetic number, because the mean of its divisors is an integer number (6235781760).
Almost surely, 2124043313255 is an apocalyptic number.
124043313255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
124043313255 is a deficient number, since it is larger than the sum of its proper divisors (75501703065).
124043313255 is a wasteful number, since it uses less digits than its factorization.
124043313255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40111.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 124043313255 its reverse (552313340421), we get a palindrome (676356653676).
The spelling of 124043313255 in words is "one hundred twenty-four billion, forty-three million, three hundred thirteen thousand, two hundred fifty-five".
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