Base | Representation |
---|---|
bin | 10010000011111000101… |
… | …001111000100000000011 |
3 | 11101122112221120220120102 |
4 | 102003320221320200003 |
5 | 130313304302411042 |
6 | 2350055210233015 |
7 | 155445111400046 |
oct | 22037051704003 |
9 | 4348487526512 |
10 | 1241122310147 |
11 | 4393a2208385 |
12 | 18065542576b |
13 | 9006402c9c5 |
14 | 440dbba0c5d |
15 | 2243eeb3b32 |
hex | 120f8a78803 |
1241122310147 has 2 divisors, whose sum is σ = 1241122310148. Its totient is φ = 1241122310146.
The previous prime is 1241122310117. The next prime is 1241122310167. The reversal of 1241122310147 is 7410132211421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1241122310147 - 238 = 966244403203 is a prime.
It is not a weakly prime, because it can be changed into another prime (1241122310117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620561155073 + 620561155074.
It is an arithmetic number, because the mean of its divisors is an integer number (620561155074).
Almost surely, 21241122310147 is an apocalyptic number.
1241122310147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241122310147 is an equidigital number, since it uses as much as digits as its factorization.
1241122310147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 1241122310147 its reverse (7410132211421), we get a palindrome (8651254521568).
The spelling of 1241122310147 in words is "one trillion, two hundred forty-one billion, one hundred twenty-two million, three hundred ten thousand, one hundred forty-seven".
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