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12411341400001 is a prime number
BaseRepresentation
bin1011010010011011110110…
…0110000110011111000001
31121221111211201111021210011
42310212331212012133001
53111321411344300001
642221405211504521
72420455416144445
oct264467546063701
947844751437704
1012411341400001
113a55690725955
121485499158141
136c04cc8ba1ab
1430c9d8120825
15167caa343d51
hexb49bd9867c1

12411341400001 has 2 divisors, whose sum is σ = 12411341400002. Its totient is φ = 12411341400000.

The previous prime is 12411341399981. The next prime is 12411341400019. The reversal of 12411341400001 is 10000414311421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9086462669376 + 3324878730625 = 3014376^2 + 1823425^2 .

It is a cyclic number.

It is not a de Polignac number, because 12411341400001 - 213 = 12411341391809 is a prime.

It is not a weakly prime, because it can be changed into another prime (12411341407001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6205670700000 + 6205670700001.

It is an arithmetic number, because the mean of its divisors is an integer number (6205670700001).

Almost surely, 212411341400001 is an apocalyptic number.

It is an amenable number.

12411341400001 is a deficient number, since it is larger than the sum of its proper divisors (1).

12411341400001 is an equidigital number, since it uses as much as digits as its factorization.

12411341400001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 12411341400001 its reverse (10000414311421), we get a palindrome (22411755711422).

The spelling of 12411341400001 in words is "twelve trillion, four hundred eleven billion, three hundred forty-one million, four hundred thousand, one".