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124115310073 is a prime number
BaseRepresentation
bin111001110010111011…
…0010101010111111001
3102212100210212000122001
41303211312111113321
54013142004410243
6133003501501001
711652456504646
oct1634566252771
9385323760561
10124115310073
1148700947527
1220079b71761
13b91c9800a1
146015b14dcd
153366406a4d
hex1ce5d955f9

124115310073 has 2 divisors, whose sum is σ = 124115310074. Its totient is φ = 124115310072.

The previous prime is 124115310061. The next prime is 124115310127. The reversal of 124115310073 is 370013511421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112410666729 + 11704643344 = 335277^2 + 108188^2 .

It is a cyclic number.

It is not a de Polignac number, because 124115310073 - 213 = 124115301881 is a prime.

It is a super-2 number, since 2×1241153100732 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (124115310673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62057655036 + 62057655037.

It is an arithmetic number, because the mean of its divisors is an integer number (62057655037).

Almost surely, 2124115310073 is an apocalyptic number.

It is an amenable number.

124115310073 is a deficient number, since it is larger than the sum of its proper divisors (1).

124115310073 is an equidigital number, since it uses as much as digits as its factorization.

124115310073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 124115310073 its reverse (370013511421), we get a palindrome (494128821494).

The spelling of 124115310073 in words is "one hundred twenty-four billion, one hundred fifteen million, three hundred ten thousand, seventy-three".