Base | Representation |
---|---|
bin | 111001110011000110… |
… | …0001100010001011011 |
3 | 102212101012122010120012 |
4 | 1303212030030101123 |
5 | 4013144441234323 |
6 | 133004224352135 |
7 | 11652556301114 |
oct | 1634614142133 |
9 | 385335563505 |
10 | 124121039963 |
11 | 48704100478 |
12 | 2007ba7564b |
13 | b920c0815b |
14 | 60167a720b |
15 | 3366b89678 |
hex | 1ce630c45b |
124121039963 has 2 divisors, whose sum is σ = 124121039964. Its totient is φ = 124121039962.
The previous prime is 124121039929. The next prime is 124121040013. The reversal of 124121039963 is 369930121421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 124121039963 - 26 = 124121039899 is a prime.
It is a super-2 number, since 2×1241210399632 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 124121039963.
It is not a weakly prime, because it can be changed into another prime (124121039923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62060519981 + 62060519982.
It is an arithmetic number, because the mean of its divisors is an integer number (62060519982).
Almost surely, 2124121039963 is an apocalyptic number.
124121039963 is a deficient number, since it is larger than the sum of its proper divisors (1).
124121039963 is an equidigital number, since it uses as much as digits as its factorization.
124121039963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 124121039963 in words is "one hundred twenty-four billion, one hundred twenty-one million, thirty-nine thousand, nine hundred sixty-three".
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