Base | Representation |
---|---|
bin | 100100111111100… |
… | …0111101110101001 |
3 | 10012111200201211212 |
4 | 1021333013232221 |
5 | 10020232032442 |
6 | 323101002505 |
7 | 42521510216 |
oct | 11177075651 |
9 | 3174621755 |
10 | 1241283497 |
11 | 587743733 |
12 | 2a7853435 |
13 | 16a21a29c |
14 | babd8b0d |
15 | 73e92a82 |
hex | 49fc7ba9 |
1241283497 has 2 divisors, whose sum is σ = 1241283498. Its totient is φ = 1241283496.
The previous prime is 1241283469. The next prime is 1241283503. The reversal of 1241283497 is 7943821421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1231729216 + 9554281 = 35096^2 + 3091^2 .
It is a cyclic number.
It is not a de Polignac number, because 1241283497 - 214 = 1241267113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1241283097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620641748 + 620641749.
It is an arithmetic number, because the mean of its divisors is an integer number (620641749).
Almost surely, 21241283497 is an apocalyptic number.
It is an amenable number.
1241283497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241283497 is an equidigital number, since it uses as much as digits as its factorization.
1241283497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96768, while the sum is 41.
The square root of 1241283497 is about 35231.8534425880. The cubic root of 1241283497 is about 1074.7076174733.
The spelling of 1241283497 in words is "one billion, two hundred forty-one million, two hundred eighty-three thousand, four hundred ninety-seven".
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