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124140226504513 is a prime number
BaseRepresentation
bin11100001110011110100110…
…000110100110011101000001
3121021112200121211101020101211
4130032132212012212131001
5112232403140441121023
61120005122135330121
735101556352623512
oct3416364606463501
9537480554336354
10124140226504513
113661163559512a
1211b0b25a820941
1354364b09c161b
1422925c1b1ca09
15e5428b174a0d
hex70e7a61a6741

124140226504513 has 2 divisors, whose sum is σ = 124140226504514. Its totient is φ = 124140226504512.

The previous prime is 124140226504423. The next prime is 124140226504627. The reversal of 124140226504513 is 315405622041421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112624031327809 + 11516195176704 = 10612447^2 + 3393552^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-124140226504513 is a prime.

It is not a weakly prime, because it can be changed into another prime (124140226594513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62070113252256 + 62070113252257.

It is an arithmetic number, because the mean of its divisors is an integer number (62070113252257).

Almost surely, 2124140226504513 is an apocalyptic number.

It is an amenable number.

124140226504513 is a deficient number, since it is larger than the sum of its proper divisors (1).

124140226504513 is an equidigital number, since it uses as much as digits as its factorization.

124140226504513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 124140226504513 its reverse (315405622041421), we get a palindrome (439545848545934).

The spelling of 124140226504513 in words is "one hundred twenty-four trillion, one hundred forty billion, two hundred twenty-six million, five hundred four thousand, five hundred thirteen".