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124141021020073 is a prime number
BaseRepresentation
bin11100001110011111010101…
…011101011011111110101001
3121021112202200012101210212001
4130032133111131123332221
5112232411302340120243
61120005333040451001
735101615141115431
oct3416372535337651
9537482605353761
10124141021020073
1136611a0301a462
1211b0b440919a61
1354365a94a4085
14229265945b2c1
15e542d5cb6a4d
hex70e7d575bfa9

124141021020073 has 2 divisors, whose sum is σ = 124141021020074. Its totient is φ = 124141021020072.

The previous prime is 124141021020041. The next prime is 124141021020097. The reversal of 124141021020073 is 370020120141421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66383255398464 + 57757765621609 = 8147592^2 + 7599853^2 .

It is a cyclic number.

It is not a de Polignac number, because 124141021020073 - 25 = 124141021020041 is a prime.

It is not a weakly prime, because it can be changed into another prime (124141021020173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62070510510036 + 62070510510037.

It is an arithmetic number, because the mean of its divisors is an integer number (62070510510037).

Almost surely, 2124141021020073 is an apocalyptic number.

It is an amenable number.

124141021020073 is a deficient number, since it is larger than the sum of its proper divisors (1).

124141021020073 is an equidigital number, since it uses as much as digits as its factorization.

124141021020073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 124141021020073 its reverse (370020120141421), we get a palindrome (494161141161494).

The spelling of 124141021020073 in words is "one hundred twenty-four trillion, one hundred forty-one billion, twenty-one million, twenty thousand, seventy-three".