Base | Representation |
---|---|
bin | 10111000111111000… |
… | …01000011001001001 |
3 | 1012001011100220221011 |
4 | 23203330020121021 |
5 | 200411004010031 |
6 | 5411501443521 |
7 | 616430220061 |
oct | 134374103111 |
9 | 35034326834 |
10 | 12414125641 |
11 | 52a04a5375 |
12 | 24a55705a1 |
13 | 122abb0798 |
14 | 85aa1c3a1 |
15 | 4c9cc46b1 |
hex | 2e3f08649 |
12414125641 has 2 divisors, whose sum is σ = 12414125642. Its totient is φ = 12414125640.
The previous prime is 12414125599. The next prime is 12414125653. The reversal of 12414125641 is 14652141421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9956048400 + 2458077241 = 99780^2 + 49579^2 .
It is a cyclic number.
It is not a de Polignac number, because 12414125641 - 217 = 12413994569 is a prime.
It is a super-2 number, since 2×124141256412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12414122641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6207062820 + 6207062821.
It is an arithmetic number, because the mean of its divisors is an integer number (6207062821).
Almost surely, 212414125641 is an apocalyptic number.
It is an amenable number.
12414125641 is a deficient number, since it is larger than the sum of its proper divisors (1).
12414125641 is an equidigital number, since it uses as much as digits as its factorization.
12414125641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7680, while the sum is 31.
The spelling of 12414125641 in words is "twelve billion, four hundred fourteen million, one hundred twenty-five thousand, six hundred forty-one".
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