1241425401343 has 4 divisors (see below), whose sum is σ = 1245469132600. Its totient is φ = 1237381670088.

The previous prime is 1241425401329. The next prime is 1241425401389. The reversal of 1241425401343 is 3431045241421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1241425401343 is a prime.

It is a super-2 number, since 2×1241425401343² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1241425401299 and 1241425401308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1241425401313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021865168 + ... + 2021865781.

It is an arithmetic number, because the mean of its divisors is an integer number (311367283150).

Almost surely, 2^{1241425401343} is an apocalyptic number.

1241425401343 is a deficient number, since it is larger than the sum of its proper divisors (4043731257).

1241425401343 is an equidigital number, since it uses as much as digits as its factorization.

1241425401343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4043731256.

The product of its (nonzero) digits is 46080, while the sum is 34.

The spelling of 1241425401343 in words is "one trillion, two hundred forty-one billion, four hundred twenty-five million, four hundred one thousand, three hundred forty-three".