Base | Representation |
---|---|
bin | 10010000100001011010… |
… | …010110111100010001001 |
3 | 11101200100202001102201212 |
4 | 102010023102313202021 |
5 | 130314424332401402 |
6 | 2350150221222505 |
7 | 155455626523352 |
oct | 22041322674211 |
9 | 4350322042655 |
10 | 1241435043977 |
11 | 439542799997 |
12 | 180722101a35 |
13 | 900b3a687cb |
14 | 4412b52ad29 |
15 | 2245c68a952 |
hex | 1210b4b7889 |
1241435043977 has 2 divisors, whose sum is σ = 1241435043978. Its totient is φ = 1241435043976.
The previous prime is 1241435043883. The next prime is 1241435044021. The reversal of 1241435043977 is 7793405341421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1229872128016 + 11562915961 = 1108996^2 + 107531^2 .
It is a cyclic number.
It is not a de Polignac number, because 1241435043977 - 224 = 1241418266761 is a prime.
It is not a weakly prime, because it can be changed into another prime (1241435043077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620717521988 + 620717521989.
It is an arithmetic number, because the mean of its divisors is an integer number (620717521989).
Almost surely, 21241435043977 is an apocalyptic number.
It is an amenable number.
1241435043977 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241435043977 is an equidigital number, since it uses as much as digits as its factorization.
1241435043977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2540160, while the sum is 50.
The spelling of 1241435043977 in words is "one trillion, two hundred forty-one billion, four hundred thirty-five million, forty-three thousand, nine hundred seventy-seven".
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