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12417770658889 is a prime number
BaseRepresentation
bin1011010010110011110011…
…0011110001110001001001
31121222010102210021110221201
42310230330303301301021
53111423043242041024
642224351201104201
72421103635015451
oct264547463616111
947863383243851
1012417770658889
113a5838a896252
121486792328061
136c0cb58a00ab
1430d047d4cd61
151680349be744
hexb4b3ccf1c49

12417770658889 has 2 divisors, whose sum is σ = 12417770658890. Its totient is φ = 12417770658888.

The previous prime is 12417770658883. The next prime is 12417770658893. The reversal of 12417770658889 is 98885607771421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12395272158864 + 22498500025 = 3520692^2 + 149995^2 .

It is an emirp because it is prime and its reverse (98885607771421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12417770658889 - 25 = 12417770658857 is a prime.

It is not a weakly prime, because it can be changed into another prime (12417770658883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6208885329444 + 6208885329445.

It is an arithmetic number, because the mean of its divisors is an integer number (6208885329445).

Almost surely, 212417770658889 is an apocalyptic number.

It is an amenable number.

12417770658889 is a deficient number, since it is larger than the sum of its proper divisors (1).

12417770658889 is an equidigital number, since it uses as much as digits as its factorization.

12417770658889 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 379330560, while the sum is 73.

The spelling of 12417770658889 in words is "twelve trillion, four hundred seventeen billion, seven hundred seventy million, six hundred fifty-eight thousand, eight hundred eighty-nine".