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1242013433 is a prime number
BaseRepresentation
bin100101000000111…
…1001111011111001
310012120001211010112
41022001321323321
510020423412213
6323124354105
742530640263
oct11201717371
93176054115
101242013433
115880a2091
122a7b45935
1316a4145bb
14bad48b33
1574088ea8
hex4a079ef9

1242013433 has 2 divisors, whose sum is σ = 1242013434. Its totient is φ = 1242013432.

The previous prime is 1242013429. The next prime is 1242013439. The reversal of 1242013433 is 3343102421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1208466169 + 33547264 = 34763^2 + 5792^2 .

It is a cyclic number.

It is not a de Polignac number, because 1242013433 - 22 = 1242013429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1242013399 and 1242013408.

It is not a weakly prime, because it can be changed into another prime (1242013439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621006716 + 621006717.

It is an arithmetic number, because the mean of its divisors is an integer number (621006717).

Almost surely, 21242013433 is an apocalyptic number.

It is an amenable number.

1242013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1242013433 is an equidigital number, since it uses as much as digits as its factorization.

1242013433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1242013433 is about 35242.2109550465. The cubic root of 1242013433 is about 1074.9182365792.

Adding to 1242013433 its reverse (3343102421), we get a palindrome (4585115854).

The spelling of 1242013433 in words is "one billion, two hundred forty-two million, thirteen thousand, four hundred thirty-three".