Base | Representation |
---|---|
bin | 1011010010111101010100… |
… | …0000111010111100001011 |
3 | 1121222101000202021220021222 |
4 | 2310233111000322330023 |
5 | 3111443311001204123 |
6 | 42225452421152255 |
7 | 2421224133061646 |
oct | 264572500727413 |
9 | 47871022256258 |
10 | 12420324241163 |
11 | 3a59480267423 |
12 | 148718555b68b |
13 | 6c1301940317 |
14 | 30d20b14aa5d |
15 | 168133c816c8 |
hex | b4bd503af0b |
12420324241163 has 2 divisors, whose sum is σ = 12420324241164. Its totient is φ = 12420324241162.
The previous prime is 12420324241123. The next prime is 12420324241243. The reversal of 12420324241163 is 36114242302421.
It is a weak prime.
It is an emirp because it is prime and its reverse (36114242302421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12420324241163 - 212 = 12420324237067 is a prime.
It is not a weakly prime, because it can be changed into another prime (12420324241123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210162120581 + 6210162120582.
It is an arithmetic number, because the mean of its divisors is an integer number (6210162120582).
Almost surely, 212420324241163 is an apocalyptic number.
12420324241163 is a deficient number, since it is larger than the sum of its proper divisors (1).
12420324241163 is an equidigital number, since it uses as much as digits as its factorization.
12420324241163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 12420324241163 its reverse (36114242302421), we get a palindrome (48534566543584).
The spelling of 12420324241163 in words is "twelve trillion, four hundred twenty billion, three hundred twenty-four million, two hundred forty-one thousand, one hundred sixty-three".
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