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1242132025415 = 5248426405083
BaseRepresentation
bin10010000100110100110…
…101101001000001000111
311101202011022112202112012
4102010310311221001013
5130322341244303130
62350343320044435
7155512122003251
oct22046465510107
94352138482465
101242132025415
11439870167406
1218089760371b
139019528bc68
1444195d1acd1
152249d963995
hex12134d69047

1242132025415 has 4 divisors (see below), whose sum is σ = 1490558430504. Its totient is φ = 993705620328.

The previous prime is 1242132025411. The next prime is 1242132025457. The reversal of 1242132025415 is 5145202312421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1242132025415 - 22 = 1242132025411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1242132025411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124213202537 + ... + 124213202546.

It is an arithmetic number, because the mean of its divisors is an integer number (372639607626).

Almost surely, 21242132025415 is an apocalyptic number.

1242132025415 is a deficient number, since it is larger than the sum of its proper divisors (248426405089).

1242132025415 is an equidigital number, since it uses as much as digits as its factorization.

1242132025415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 248426405088.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1242132025415 its reverse (5145202312421), we get a palindrome (6387334337836).

The spelling of 1242132025415 in words is "one trillion, two hundred forty-two billion, one hundred thirty-two million, twenty-five thousand, four hundred fifteen".

Divisors: 1 5 248426405083 1242132025415