Base | Representation |
---|---|
bin | 11100001111100100101000… |
… | …100101110000110001000011 |
3 | 121021210212201220022112020111 |
4 | 130033210220211300301003 |
5 | 112240121200104432311 |
6 | 1120103440354452151 |
7 | 35110161104252014 |
oct | 3417445045606103 |
9 | 537725656275214 |
10 | 124215430155331 |
11 | 36640517040069 |
12 | 11b21948294057 |
13 | 544060722c7a8 |
14 | 22960b788900b |
15 | e561dd517d21 |
hex | 70f928970c43 |
124215430155331 has 2 divisors, whose sum is σ = 124215430155332. Its totient is φ = 124215430155330.
The previous prime is 124215430155263. The next prime is 124215430155373. The reversal of 124215430155331 is 133551034512421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124215430155331 - 219 = 124215429631043 is a prime.
It is a super-2 number, since 2×1242154301553312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (124215430155391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62107715077665 + 62107715077666.
It is an arithmetic number, because the mean of its divisors is an integer number (62107715077666).
Almost surely, 2124215430155331 is an apocalyptic number.
124215430155331 is a deficient number, since it is larger than the sum of its proper divisors (1).
124215430155331 is an equidigital number, since it uses as much as digits as its factorization.
124215430155331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 124215430155331 its reverse (133551034512421), we get a palindrome (257766464667752).
The spelling of 124215430155331 in words is "one hundred twenty-four trillion, two hundred fifteen billion, four hundred thirty million, one hundred fifty-five thousand, three hundred thirty-one".
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