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124215430155331 is a prime number
BaseRepresentation
bin11100001111100100101000…
…100101110000110001000011
3121021210212201220022112020111
4130033210220211300301003
5112240121200104432311
61120103440354452151
735110161104252014
oct3417445045606103
9537725656275214
10124215430155331
1136640517040069
1211b21948294057
13544060722c7a8
1422960b788900b
15e561dd517d21
hex70f928970c43

124215430155331 has 2 divisors, whose sum is σ = 124215430155332. Its totient is φ = 124215430155330.

The previous prime is 124215430155263. The next prime is 124215430155373. The reversal of 124215430155331 is 133551034512421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 124215430155331 - 219 = 124215429631043 is a prime.

It is a super-2 number, since 2×1242154301553312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (124215430155391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62107715077665 + 62107715077666.

It is an arithmetic number, because the mean of its divisors is an integer number (62107715077666).

Almost surely, 2124215430155331 is an apocalyptic number.

124215430155331 is a deficient number, since it is larger than the sum of its proper divisors (1).

124215430155331 is an equidigital number, since it uses as much as digits as its factorization.

124215430155331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 124215430155331 its reverse (133551034512421), we get a palindrome (257766464667752).

The spelling of 124215430155331 in words is "one hundred twenty-four trillion, two hundred fifteen billion, four hundred thirty million, one hundred fifty-five thousand, three hundred thirty-one".