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12424421341 = 13194842911
BaseRepresentation
bin10111001001000110…
…11001111111011101
31012001212201222222101
423210203121333131
5200421122440331
65412510245101
7616613560513
oct134443317735
935055658871
1012424421341
1152a6297712
1224a8ab6791
131230076b07
1485c13c4b3
154cab5a061
hex2e48d9fdd

12424421341 has 4 divisors (see below), whose sum is σ = 12519264384. Its totient is φ = 12329578300.

The previous prime is 12424421323. The next prime is 12424421351. The reversal of 12424421341 is 14312442421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12424421341 - 225 = 12390866909 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12424421311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47421325 + ... + 47421586.

It is an arithmetic number, because the mean of its divisors is an integer number (3129816096).

Almost surely, 212424421341 is an apocalyptic number.

It is an amenable number.

12424421341 is a deficient number, since it is larger than the sum of its proper divisors (94843043).

12424421341 is an equidigital number, since it uses as much as digits as its factorization.

12424421341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94843042.

The product of its digits is 6144, while the sum is 28.

Adding to 12424421341 its reverse (14312442421), we get a palindrome (26736863762).

The spelling of 12424421341 in words is "twelve billion, four hundred twenty-four million, four hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 131 94842911 12424421341