Base | Representation |
---|---|
bin | 1011010011011011100111… |
… | …0110111000100111011011 |
3 | 1122000011000122110002221122 |
4 | 2310312321312320213123 |
5 | 3112111440342404323 |
6 | 42233315515555455 |
7 | 2421632534461055 |
oct | 264667166704733 |
9 | 48004018402848 |
10 | 12428458559963 |
11 | 3a61974936546 |
12 | 148887575bb8b |
13 | 6c1cc9c51904 |
14 | 30d77d5ba8d5 |
15 | 16845ce5eec8 |
hex | b4db9db89db |
12428458559963 has 2 divisors, whose sum is σ = 12428458559964. Its totient is φ = 12428458559962.
The previous prime is 12428458559947. The next prime is 12428458560019. The reversal of 12428458559963 is 36995585482421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12428458559963 - 24 = 12428458559947 is a prime.
It is a super-2 number, since 2×124284585599632 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12428458559903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6214229279981 + 6214229279982.
It is an arithmetic number, because the mean of its divisors is an integer number (6214229279982).
Almost surely, 212428458559963 is an apocalyptic number.
12428458559963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12428458559963 is an equidigital number, since it uses as much as digits as its factorization.
12428458559963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 746496000, while the sum is 71.
The spelling of 12428458559963 in words is "twelve trillion, four hundred twenty-eight billion, four hundred fifty-eight million, five hundred fifty-nine thousand, nine hundred sixty-three".
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