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12430034356153 is a prime number
BaseRepresentation
bin1011010011100001011111…
…0010000100011110111001
31122000022002110120211221111
42310320113302010132321
53112123202243344103
642234140130440321
72422016560513051
oct264702762043671
948008073524844
1012430034356153
113a62603386547
1214890354330a1
136c21bb5619ab
1430d88c9b0561
1516850147c86d
hexb4e17c847b9

12430034356153 has 2 divisors, whose sum is σ = 12430034356154. Its totient is φ = 12430034356152.

The previous prime is 12430034356147. The next prime is 12430034356199. The reversal of 12430034356153 is 35165343003421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10829121122169 + 1600913233984 = 3290763^2 + 1265272^2 .

It is a cyclic number.

It is not a de Polignac number, because 12430034356153 - 213 = 12430034347961 is a prime.

It is not a weakly prime, because it can be changed into another prime (12430034356853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6215017178076 + 6215017178077.

It is an arithmetic number, because the mean of its divisors is an integer number (6215017178077).

Almost surely, 212430034356153 is an apocalyptic number.

It is an amenable number.

12430034356153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12430034356153 is an equidigital number, since it uses as much as digits as its factorization.

12430034356153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 12430034356153 its reverse (35165343003421), we get a palindrome (47595377359574).

The spelling of 12430034356153 in words is "twelve trillion, four hundred thirty billion, thirty-four million, three hundred fifty-six thousand, one hundred fifty-three".