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1243043324113 is a prime number
BaseRepresentation
bin10010000101101011001…
…001111110000011010001
311101211111211022112022211
4102011223021332003101
5130331223042332423
62351013552232121
7155543525630623
oct22055311760321
94354454275284
101243043324113
1143a198606628
12180ab083b641
13902ac010366
1444240d78c13
152250397310d
hex1216b27e0d1

1243043324113 has 2 divisors, whose sum is σ = 1243043324114. Its totient is φ = 1243043324112.

The previous prime is 1243043324051. The next prime is 1243043324141. The reversal of 1243043324113 is 3114233403421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1017501916369 + 225541407744 = 1008713^2 + 474912^2 .

It is a cyclic number.

It is not a de Polignac number, because 1243043324113 - 221 = 1243041226961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1243043324813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621521662056 + 621521662057.

It is an arithmetic number, because the mean of its divisors is an integer number (621521662057).

Almost surely, 21243043324113 is an apocalyptic number.

It is an amenable number.

1243043324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243043324113 is an equidigital number, since it uses as much as digits as its factorization.

1243043324113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1243043324113 its reverse (3114233403421), we get a palindrome (4357276727534).

The spelling of 1243043324113 in words is "one trillion, two hundred forty-three billion, forty-three million, three hundred twenty-four thousand, one hundred thirteen".