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12431354147 is a prime number
BaseRepresentation
bin10111001001111011…
…10110100100100011
31012002100210012222222
423210331312210203
5200424411313042
65413315021255
7620026524002
oct134475664443
935070705888
1012431354147
1152aa1a2403
1224ab29a82b
131231633574
1485d024c39
154cb5792d2
hex2e4f76923

12431354147 has 2 divisors, whose sum is σ = 12431354148. Its totient is φ = 12431354146.

The previous prime is 12431354099. The next prime is 12431354153. The reversal of 12431354147 is 74145313421.

It is a strong prime.

It is an emirp because it is prime and its reverse (74145313421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12431354147 is a prime.

It is not a weakly prime, because it can be changed into another prime (12431354167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6215677073 + 6215677074.

It is an arithmetic number, because the mean of its divisors is an integer number (6215677074).

Almost surely, 212431354147 is an apocalyptic number.

12431354147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12431354147 is an equidigital number, since it uses as much as digits as its factorization.

12431354147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40320, while the sum is 35.

Adding to 12431354147 its reverse (74145313421), we get a palindrome (86576667568).

The spelling of 12431354147 in words is "twelve billion, four hundred thirty-one million, three hundred fifty-four thousand, one hundred forty-seven".