Base | Representation |
---|---|
bin | 1011010011101010010011… |
… | …1010000101010100101011 |
3 | 1122000112012110210212100111 |
4 | 2310322210322011110223 |
5 | 3112143024410403303 |
6 | 42235211110315151 |
7 | 2422132340521501 |
oct | 264724472052453 |
9 | 48015173725314 |
10 | 12432402044203 |
11 | 3a63608929629 |
12 | 1489596358ab7 |
13 | 6c24a7c4623b |
14 | 30da3521c671 |
15 | 1685de26eb6d |
hex | b4ea4e8552b |
12432402044203 has 2 divisors, whose sum is σ = 12432402044204. Its totient is φ = 12432402044202.
The previous prime is 12432402044171. The next prime is 12432402044267. The reversal of 12432402044203 is 30244020423421.
12432402044203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12432402044203 - 25 = 12432402044171 is a prime.
It is not a weakly prime, because it can be changed into another prime (12432402047203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216201022101 + 6216201022102.
It is an arithmetic number, because the mean of its divisors is an integer number (6216201022102).
Almost surely, 212432402044203 is an apocalyptic number.
12432402044203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12432402044203 is an equidigital number, since it uses as much as digits as its factorization.
12432402044203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 12432402044203 its reverse (30244020423421), we get a palindrome (42676422467624).
The spelling of 12432402044203 in words is "twelve trillion, four hundred thirty-two billion, four hundred two million, forty-four thousand, two hundred three".
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