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12433115053 = 17731359709
BaseRepresentation
bin10111001010001001…
…00100011110101101
31012002111002200111201
423211010210132231
5200430334140203
65413420445501
7620050506562
oct134504443655
935074080451
1012433115053
1153001953a7
1224ab9a9891
131231acbc18
1485d362869
154cb7c5e1d
hex2e51247ad

12433115053 has 4 divisors (see below), whose sum is σ = 13164474780. Its totient is φ = 11701755328.

The previous prime is 12433115029. The next prime is 12433115089. The reversal of 12433115053 is 35051133421.

It is a happy number.

12433115053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3525153129 + 8907961924 = 59373^2 + 94382^2 .

It is a cyclic number.

It is not a de Polignac number, because 12433115053 - 221 = 12431017901 is a prime.

It is a super-2 number, since 2×124331150532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12433118053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365679838 + ... + 365679871.

It is an arithmetic number, because the mean of its divisors is an integer number (3291118695).

Almost surely, 212433115053 is an apocalyptic number.

It is an amenable number.

12433115053 is a deficient number, since it is larger than the sum of its proper divisors (731359727).

12433115053 is an equidigital number, since it uses as much as digits as its factorization.

12433115053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 731359726.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 12433115053 its reverse (35051133421), we get a palindrome (47484248474).

The spelling of 12433115053 in words is "twelve billion, four hundred thirty-three million, one hundred fifteen thousand, fifty-three".

Divisors: 1 17 731359709 12433115053