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12433142003 is a prime number
BaseRepresentation
bin10111001010001001…
…01011000011110011
31012002111011001110212
423211010223003303
5200430341021003
65413421214335
7620050651262
oct134504530363
935074131425
1012433142003
115300203677
1224aba013ab
131231b0b279
1485d36c5d9
154cb7cddd8
hex2e512b0f3

12433142003 has 2 divisors, whose sum is σ = 12433142004. Its totient is φ = 12433142002.

The previous prime is 12433141999. The next prime is 12433142009. The reversal of 12433142003 is 30024133421.

12433142003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30024133421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12433142003 - 22 = 12433141999 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12433142003.

It is not a weakly prime, because it can be changed into another prime (12433142009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216571001 + 6216571002.

It is an arithmetic number, because the mean of its divisors is an integer number (6216571002).

Almost surely, 212433142003 is an apocalyptic number.

12433142003 is a deficient number, since it is larger than the sum of its proper divisors (1).

12433142003 is an equidigital number, since it uses as much as digits as its factorization.

12433142003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 12433142003 its reverse (30024133421), we get a palindrome (42457275424).

The spelling of 12433142003 in words is "twelve billion, four hundred thirty-three million, one hundred forty-two thousand, three".