Base | Representation |
---|---|
bin | 111001111001011100… |
… | …1010110001000011111 |
3 | 102212221001201221212011 |
4 | 1303302321112020133 |
5 | 4014114024002143 |
6 | 133041321252051 |
7 | 11661055201663 |
oct | 1636271261037 |
9 | 385831657764 |
10 | 124334203423 |
11 | 48803464321 |
12 | 2011b334027 |
13 | b956120b91 |
14 | 6036c148a3 |
15 | 337a743e9d |
hex | 1cf2e5621f |
124334203423 has 4 divisors (see below), whose sum is σ = 124337659968. Its totient is φ = 124330746880.
The previous prime is 124334203397. The next prime is 124334203439. The reversal of 124334203423 is 324302433421.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 324302433421 = 37 ⋅8764930633.
It is a cyclic number.
It is not a de Polignac number, because 124334203423 - 25 = 124334203391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124334203463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1673743 + ... + 1746448.
It is an arithmetic number, because the mean of its divisors is an integer number (31084414992).
Almost surely, 2124334203423 is an apocalyptic number.
124334203423 is a deficient number, since it is larger than the sum of its proper divisors (3456545).
124334203423 is an equidigital number, since it uses as much as digits as its factorization.
124334203423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3456544.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 124334203423 its reverse (324302433421), we get a palindrome (448636636844).
The spelling of 124334203423 in words is "one hundred twenty-four billion, three hundred thirty-four million, two hundred three thousand, four hundred twenty-three".
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