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12433437627673 is a prime number
BaseRepresentation
bin1011010011101110001010…
…1000100001010100011001
31122000121212122102221210211
42310323202220201110121
53112202140013041143
642235501542411121
72422200114034336
oct264734250412431
948017778387724
1012433437627673
113a63a9a446837
121489825130aa1
136c261166191a
1430dad298d98d
1516865012e49d
hexb4ee2a21519

12433437627673 has 2 divisors, whose sum is σ = 12433437627674. Its totient is φ = 12433437627672.

The previous prime is 12433437627661. The next prime is 12433437627683. The reversal of 12433437627673 is 37672673433421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12433437627664 + 9 = 3526108^2 + 3^2 .

It is a cyclic number.

It is not a de Polignac number, because 12433437627673 - 25 = 12433437627641 is a prime.

It is not a weakly prime, because it can be changed into another prime (12433437627623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216718813836 + 6216718813837.

It is an arithmetic number, because the mean of its divisors is an integer number (6216718813837).

Almost surely, 212433437627673 is an apocalyptic number.

It is an amenable number.

12433437627673 is a deficient number, since it is larger than the sum of its proper divisors (1).

12433437627673 is an equidigital number, since it uses as much as digits as its factorization.

12433437627673 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64012032, while the sum is 58.

The spelling of 12433437627673 in words is "twelve trillion, four hundred thirty-three billion, four hundred thirty-seven million, six hundred twenty-seven thousand, six hundred seventy-three".