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12434050253 = 106311697131
BaseRepresentation
bin10111001010010000…
…01000110011001101
31012002112212012100202
423211020020303031
5200431104102003
65413452503245
7620061453242
oct134510106315
935075765322
1012434050253
115300773a99
1224b017ab25
1312320687b1
1485d5275c9
154cb90d088
hex2e5208ccd

12434050253 has 4 divisors (see below), whose sum is σ = 12445748448. Its totient is φ = 12422352060.

The previous prime is 12434050247. The next prime is 12434050301. The reversal of 12434050253 is 35205043421.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12434050253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12434050553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5847503 + ... + 5849628.

It is an arithmetic number, because the mean of its divisors is an integer number (3111437112).

Almost surely, 212434050253 is an apocalyptic number.

It is an amenable number.

12434050253 is a deficient number, since it is larger than the sum of its proper divisors (11698195).

12434050253 is a wasteful number, since it uses less digits than its factorization.

12434050253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11698194.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 12434050253 its reverse (35205043421), we get a palindrome (47639093674).

The spelling of 12434050253 in words is "twelve billion, four hundred thirty-four million, fifty thousand, two hundred fifty-three".

Divisors: 1 1063 11697131 12434050253