Base | Representation |
---|---|
bin | 1011010011110101010000… |
… | …0110010011011011100001 |
3 | 1122000210210022110112010211 |
4 | 2310331110012103123201 |
5 | 3112220034330314023 |
6 | 42240414504054121 |
7 | 2422265230454323 |
oct | 264752406233341 |
9 | 48023708415124 |
10 | 12435341260513 |
11 | 3a64886a53316 |
12 | 148a076764341 |
13 | 6c2855b67ba2 |
14 | 30dc33721613 |
15 | 168712308a0d |
hex | b4f541936e1 |
12435341260513 has 2 divisors, whose sum is σ = 12435341260514. Its totient is φ = 12435341260512.
The previous prime is 12435341260493. The next prime is 12435341260561. The reversal of 12435341260513 is 31506214353421.
12435341260513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12364344592209 + 70996668304 = 3516297^2 + 266452^2 .
It is a cyclic number.
It is not a de Polignac number, because 12435341260513 - 25 = 12435341260481 is a prime.
It is not a weakly prime, because it can be changed into another prime (12435341260213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6217670630256 + 6217670630257.
It is an arithmetic number, because the mean of its divisors is an integer number (6217670630257).
Almost surely, 212435341260513 is an apocalyptic number.
It is an amenable number.
12435341260513 is a deficient number, since it is larger than the sum of its proper divisors (1).
12435341260513 is an equidigital number, since it uses as much as digits as its factorization.
12435341260513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 12435341260513 in words is "twelve trillion, four hundred thirty-five billion, three hundred forty-one million, two hundred sixty thousand, five hundred thirteen".
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