Base | Representation |
---|---|
bin | 10010000110011011011… |
… | …110111101111110011001 |
3 | 11101220121100000000000211 |
4 | 102012123132331332121 |
5 | 130334403124311233 |
6 | 2351230234531121 |
7 | 155602602462415 |
oct | 22063336757631 |
9 | 4356540000024 |
10 | 1243854135193 |
11 | 43a574260a2a |
12 | 181098296aa1 |
13 | 903aacaa027 |
14 | 442ba919d45 |
15 | 2254ec335cd |
hex | 1219b7bdf99 |
1243854135193 has 2 divisors, whose sum is σ = 1243854135194. Its totient is φ = 1243854135192.
The previous prime is 1243854135163. The next prime is 1243854135221. The reversal of 1243854135193 is 3915314583421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1191223810624 + 52630324569 = 1091432^2 + 229413^2 .
It is a cyclic number.
It is not a de Polignac number, because 1243854135193 - 217 = 1243854004121 is a prime.
It is a super-2 number, since 2×12438541351932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1243854135103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621927067596 + 621927067597.
It is an arithmetic number, because the mean of its divisors is an integer number (621927067597).
Almost surely, 21243854135193 is an apocalyptic number.
It is an amenable number.
1243854135193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1243854135193 is an equidigital number, since it uses as much as digits as its factorization.
1243854135193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1555200, while the sum is 49.
The spelling of 1243854135193 in words is "one trillion, two hundred forty-three billion, eight hundred fifty-four million, one hundred thirty-five thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.104 sec. • engine limits •