Base | Representation |
---|---|
bin | 10010000110100101110… |
… | …100000000001000001001 |
3 | 11101221001102001211201211 |
4 | 102012211310000020021 |
5 | 130340232004434233 |
6 | 2351255345013121 |
7 | 155610105415414 |
oct | 22064564001011 |
9 | 4357042054654 |
10 | 1244027421193 |
11 | 43a6530582a7 |
12 | 1811263241a1 |
13 | 90407b6cc1b |
14 | 442d5946b7b |
15 | 225600625cd |
hex | 121a5d00209 |
1244027421193 has 2 divisors, whose sum is σ = 1244027421194. Its totient is φ = 1244027421192.
The previous prime is 1244027421167. The next prime is 1244027421277. The reversal of 1244027421193 is 3911247204421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 886409069049 + 357618352144 = 941493^2 + 598012^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1244027421193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1244027421293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622013710596 + 622013710597.
It is an arithmetic number, because the mean of its divisors is an integer number (622013710597).
Almost surely, 21244027421193 is an apocalyptic number.
It is an amenable number.
1244027421193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244027421193 is an equidigital number, since it uses as much as digits as its factorization.
1244027421193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 1244027421193 in words is "one trillion, two hundred forty-four billion, twenty-seven million, four hundred twenty-one thousand, one hundred ninety-three".
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