12440434403 has 4 divisors (see below), whose sum is σ = 13172224680. Its totient is φ = 11708644128.

The previous prime is 12440434309. The next prime is 12440434417. The reversal of 12440434403 is 30443404421.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30443404421 = 53 ⋅574403857.

It is a cyclic number.

It is not a de Polignac number, because 12440434403 - 2⁸ = 12440434147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12440434423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365895113 + ... + 365895146.

It is an arithmetic number, because the mean of its divisors is an integer number (3293056170).

Almost surely, 2^12440434403 is an apocalyptic number.

12440434403 is a deficient number, since it is larger than the sum of its proper divisors (731790277).

12440434403 is an equidigital number, since it uses as much as digits as its factorization.

12440434403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 731790276.

The product of its (nonzero) digits is 18432, while the sum is 29.

Adding to 12440434403 its reverse (30443404421), we get a palindrome (42883838824).

The spelling of 12440434403 in words is "twelve billion, four hundred forty million, four hundred thirty-four thousand, four hundred three".