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12441004000993 is a prime number
BaseRepresentation
bin1011010100001010010110…
…0111111100011011100001
31122001100101221220112201201
42311002211213330123201
53112313134011012433
642243152432201201
72422555451120641
oct265024547743341
948040357815651
1012441004000993
113a67222471027
12148b197099201
136c32490bb7b9
1431020d81c521
15168944522a7d
hexb50a59fc6e1

12441004000993 has 2 divisors, whose sum is σ = 12441004000994. Its totient is φ = 12441004000992.

The previous prime is 12441004000969. The next prime is 12441004001033. The reversal of 12441004000993 is 39900040014421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12275654417569 + 165349583424 = 3503663^2 + 406632^2 .

It is a cyclic number.

It is not a de Polignac number, because 12441004000993 - 213 = 12441003992801 is a prime.

It is not a weakly prime, because it can be changed into another prime (12441004003993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220502000496 + 6220502000497.

It is an arithmetic number, because the mean of its divisors is an integer number (6220502000497).

Almost surely, 212441004000993 is an apocalyptic number.

It is an amenable number.

12441004000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12441004000993 is an equidigital number, since it uses as much as digits as its factorization.

12441004000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 12441004000993 in words is "twelve trillion, four hundred forty-one billion, four million, nine hundred ninety-three", and thus it is an aban number.