Base | Representation |
---|---|
bin | 1011010100001010110011… |
… | …0010100110010001100111 |
3 | 1122001100201100011000212202 |
4 | 2311002230302212101213 |
5 | 3112313410300444333 |
6 | 42243212405205115 |
7 | 2422561441103330 |
oct | 265025462462147 |
9 | 48040640130782 |
10 | 12441124234343 |
11 | 3a67284322132 |
12 | 148b20b40079b |
13 | 6c3267c979ac |
14 | 310221799287 |
15 | 16894ed725e8 |
hex | b50acca6467 |
12441124234343 has 16 divisors (see below), whose sum is σ = 14254794732864. Its totient is φ = 10636547581440.
The previous prime is 12441124234313. The next prime is 12441124234351. The reversal of 12441124234343 is 34343242114421.
It is a cyclic number.
It is not a de Polignac number, because 12441124234343 - 28 = 12441124234087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12441124234297 and 12441124234306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12441124234313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87581471 + ... + 87723407.
It is an arithmetic number, because the mean of its divisors is an integer number (890924670804).
Almost surely, 212441124234343 is an apocalyptic number.
12441124234343 is a deficient number, since it is larger than the sum of its proper divisors (1813670498521).
12441124234343 is a wasteful number, since it uses less digits than its factorization.
12441124234343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173882.
The product of its digits is 221184, while the sum is 38.
Adding to 12441124234343 its reverse (34343242114421), we get a palindrome (46784366348764).
The spelling of 12441124234343 in words is "twelve trillion, four hundred forty-one billion, one hundred twenty-four million, two hundred thirty-four thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •