Base | Representation |
---|---|
bin | 11100010010101100101010… |
… | …001100110101100000110101 |
3 | 121022120102002222002112200010 |
4 | 130102230222030311200311 |
5 | 112302131030104243110 |
6 | 1120350240340410433 |
7 | 35131533330021312 |
oct | 3422545214654065 |
9 | 538512088075603 |
10 | 124430205540405 |
11 | 36713610158806 |
12 | 11b574a80a6a19 |
13 | 54579446a286b |
14 | 22a2650001d09 |
15 | e5baadbd4020 |
hex | 712b2a335835 |
124430205540405 has 16 divisors (see below), whose sum is σ = 200608087103424. Its totient is φ = 65856190208640.
The previous prime is 124430205540341. The next prime is 124430205540427. The reversal of 124430205540405 is 504045502034421.
It is not a de Polignac number, because 124430205540405 - 26 = 124430205540341 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31661627944 + ... + 31661631873.
It is an arithmetic number, because the mean of its divisors is an integer number (12538005443964).
Almost surely, 2124430205540405 is an apocalyptic number.
124430205540405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
124430205540405 is a deficient number, since it is larger than the sum of its proper divisors (76177881563019).
124430205540405 is a wasteful number, since it uses less digits than its factorization.
124430205540405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63323259956.
The product of its (nonzero) digits is 384000, while the sum is 39.
Adding to 124430205540405 its reverse (504045502034421), we get a palindrome (628475707574826).
The spelling of 124430205540405 in words is "one hundred twenty-four trillion, four hundred thirty billion, two hundred five million, five hundred forty thousand, four hundred five".
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