Base | Representation |
---|---|
bin | 1011010100010001110111… |
… | …1110010100111100101111 |
3 | 1122001112121200021011012121 |
4 | 2311010131332110330233 |
5 | 3112331302410301021 |
6 | 42244125041213411 |
7 | 2422656466352404 |
oct | 265043576247457 |
9 | 48045550234177 |
10 | 12443023134511 |
11 | 3a68069196a12 |
12 | 148b65b331267 |
13 | 6c34ab504a68 |
14 | 310361a582ab |
15 | 168a11914741 |
hex | b511df94f2f |
12443023134511 has 4 divisors (see below), whose sum is σ = 12872092897800. Its totient is φ = 12013953371224.
The previous prime is 12443023134463. The next prime is 12443023134517. The reversal of 12443023134511 is 11543132034421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12443023134511 - 233 = 12434433199919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12443023134517) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214534881601 + ... + 214534881658.
It is an arithmetic number, because the mean of its divisors is an integer number (3218023224450).
Almost surely, 212443023134511 is an apocalyptic number.
12443023134511 is a deficient number, since it is larger than the sum of its proper divisors (429069763289).
12443023134511 is an equidigital number, since it uses as much as digits as its factorization.
12443023134511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429069763288.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 12443023134511 its reverse (11543132034421), we get a palindrome (23986155168932).
The spelling of 12443023134511 in words is "twelve trillion, four hundred forty-three billion, twenty-three million, one hundred thirty-four thousand, five hundred eleven".
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