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124435120153 is a prime number
BaseRepresentation
bin111001111100011101…
…0010100000000011001
3102220012002122001120211
41303320322110000121
54014320342321103
6133055324251121
711663422032601
oct1637072240031
9386162561524
10124435120153
1148855421583
12201490a0aa1
13b970cc5a16
1460463a3c01
15338452a36d
hex1cf8e94019

124435120153 has 2 divisors, whose sum is σ = 124435120154. Its totient is φ = 124435120152.

The previous prime is 124435120079. The next prime is 124435120181. The reversal of 124435120153 is 351021534421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121904325904 + 2530794249 = 349148^2 + 50307^2 .

It is an emirp because it is prime and its reverse (351021534421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-124435120153 is a prime.

It is not a weakly prime, because it can be changed into another prime (124435720153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62217560076 + 62217560077.

It is an arithmetic number, because the mean of its divisors is an integer number (62217560077).

Almost surely, 2124435120153 is an apocalyptic number.

It is an amenable number.

124435120153 is a deficient number, since it is larger than the sum of its proper divisors (1).

124435120153 is an equidigital number, since it uses as much as digits as its factorization.

124435120153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 124435120153 its reverse (351021534421), we get a palindrome (475456654574).

The spelling of 124435120153 in words is "one hundred twenty-four billion, four hundred thirty-five million, one hundred twenty thousand, one hundred fifty-three".