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12444127 = 23541049
BaseRepresentation
bin101111011110…
…000111011111
3212102020010121
4233132013133
511141203002
61122415411
7210526153
oct57360737
925366117
1012444127
11702a503
124201567
1327691b7
14191d063
15115c237
hexbde1df

12444127 has 4 divisors (see below), whose sum is σ = 12985200. Its totient is φ = 11903056.

The previous prime is 12444097. The next prime is 12444137. The reversal of 12444127 is 72144421.

12444127 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12444127 - 27 = 12443999 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12444137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270502 + ... + 270547.

It is an arithmetic number, because the mean of its divisors is an integer number (3246300).

Almost surely, 212444127 is an apocalyptic number.

12444127 is a deficient number, since it is larger than the sum of its proper divisors (541073).

12444127 is an equidigital number, since it uses as much as digits as its factorization.

12444127 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 541072.

The product of its digits is 1792, while the sum is 25.

The square root of 12444127 is about 3527.6234209450. The cubic root of 12444127 is about 231.7331392042.

Adding to 12444127 its reverse (72144421), we get a palindrome (84588548).

The spelling of 12444127 in words is "twelve million, four hundred forty-four thousand, one hundred twenty-seven".

Divisors: 1 23 541049 12444127