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12444141433 is a prime number
BaseRepresentation
bin10111001011011101…
…01000011101111001
31012010020211212212011
423211232220131321
5200441200011213
65414453045521
7620243312503
oct134556503571
935106755764
1012444141433
115306436709
1224b36268a1
13123418c9c9
148609d2d73
154cc75303d
hex2e5ba8779

12444141433 has 2 divisors, whose sum is σ = 12444141434. Its totient is φ = 12444141432.

The previous prime is 12444141407. The next prime is 12444141499. The reversal of 12444141433 is 33414144421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8643049024 + 3801092409 = 92968^2 + 61653^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12444141433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12444141395 and 12444141404.

It is not a weakly prime, because it can be changed into another prime (12444141403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6222070716 + 6222070717.

It is an arithmetic number, because the mean of its divisors is an integer number (6222070717).

Almost surely, 212444141433 is an apocalyptic number.

It is an amenable number.

12444141433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12444141433 is an equidigital number, since it uses as much as digits as its factorization.

12444141433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18432, while the sum is 31.

Adding to 12444141433 its reverse (33414144421), we get a palindrome (45858285854).

The spelling of 12444141433 in words is "twelve billion, four hundred forty-four million, one hundred forty-one thousand, four hundred thirty-three".