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1244440200103 = 1965496852637
BaseRepresentation
bin10010000110111110011…
…010101000001110100111
311101222010011210011221121
4102012332122220032213
5130342103142400403
62351404332154411
7155623250112442
oct22067632501647
94358104704847
101244440200103
1143a8450611a1
12181220608a07
1390472536bb9
14443346b6659
15225863ec3bd
hex121be6a83a7

1244440200103 has 4 divisors (see below), whose sum is σ = 1309937052760. Its totient is φ = 1178943347448.

The previous prime is 1244440200097. The next prime is 1244440200169. The reversal of 1244440200103 is 3010020444421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1244440200103 - 25 = 1244440200071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1244440210103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32748426300 + ... + 32748426337.

It is an arithmetic number, because the mean of its divisors is an integer number (327484263190).

Almost surely, 21244440200103 is an apocalyptic number.

1244440200103 is a deficient number, since it is larger than the sum of its proper divisors (65496852657).

1244440200103 is an equidigital number, since it uses as much as digits as its factorization.

1244440200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65496852656.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 1244440200103 its reverse (3010020444421), we get a palindrome (4254460644524).

The spelling of 1244440200103 in words is "one trillion, two hundred forty-four billion, four hundred forty million, two hundred thousand, one hundred three".

Divisors: 1 19 65496852637 1244440200103