Base | Representation |
---|---|
bin | 10111001100001111… |
… | …01111110011111001 |
3 | 1012010201020100222011 |
4 | 23212013233303321 |
5 | 200444341200423 |
6 | 5415250125521 |
7 | 620353263061 |
oct | 134607576371 |
9 | 35121210864 |
10 | 12450725113 |
11 | 530a123072 |
12 | 24b58808a1 |
13 | 1235656588 |
14 | 8618283a1 |
15 | 4cd103b0d |
hex | 2e61efcf9 |
12450725113 has 2 divisors, whose sum is σ = 12450725114. Its totient is φ = 12450725112.
The previous prime is 12450725107. The next prime is 12450725117. The reversal of 12450725113 is 31152705421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11916560569 + 534164544 = 109163^2 + 23112^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12450725113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12450725117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6225362556 + 6225362557.
It is an arithmetic number, because the mean of its divisors is an integer number (6225362557).
Almost surely, 212450725113 is an apocalyptic number.
It is an amenable number.
12450725113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12450725113 is an equidigital number, since it uses as much as digits as its factorization.
12450725113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
The spelling of 12450725113 in words is "twelve billion, four hundred fifty million, seven hundred twenty-five thousand, one hundred thirteen".
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