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12450736139983 = 53234919549811
BaseRepresentation
bin1011010100101110100110…
…1101000110111011001111
31122002021112012122102121221
42311023221231012323033
53112443101422434413
642251442245504211
72423351564001001
oct265135155067317
948067465572557
1012450736139983
113a70366a630a9
121491052412067
136c413a45191b
14310894176371
15168d13b1e68d
hexb52e9b46ecf

12450736139983 has 4 divisors (see below), whose sum is σ = 12685655689848. Its totient is φ = 12215816590120.

The previous prime is 12450736139971. The next prime is 12450736140083. The reversal of 12450736139983 is 38993163705421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12450736139983 - 213 = 12450736131791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12450736134983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117459774853 + ... + 117459774958.

It is an arithmetic number, because the mean of its divisors is an integer number (3171413922462).

It is a 1-persistent number, because it is pandigital, but 2⋅12450736139983 = 24901472279966 is not.

Almost surely, 212450736139983 is an apocalyptic number.

12450736139983 is a deficient number, since it is larger than the sum of its proper divisors (234919549865).

12450736139983 is an equidigital number, since it uses as much as digits as its factorization.

12450736139983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234919549864.

The product of its (nonzero) digits is 29393280, while the sum is 61.

The spelling of 12450736139983 in words is "twelve trillion, four hundred fifty billion, seven hundred thirty-six million, one hundred thirty-nine thousand, nine hundred eighty-three".

Divisors: 1 53 234919549811 12450736139983