Base | Representation |
---|---|
bin | 1011010100101110100110… |
… | …1101000110111011001111 |
3 | 1122002021112012122102121221 |
4 | 2311023221231012323033 |
5 | 3112443101422434413 |
6 | 42251442245504211 |
7 | 2423351564001001 |
oct | 265135155067317 |
9 | 48067465572557 |
10 | 12450736139983 |
11 | 3a70366a630a9 |
12 | 1491052412067 |
13 | 6c413a45191b |
14 | 310894176371 |
15 | 168d13b1e68d |
hex | b52e9b46ecf |
12450736139983 has 4 divisors (see below), whose sum is σ = 12685655689848. Its totient is φ = 12215816590120.
The previous prime is 12450736139971. The next prime is 12450736140083. The reversal of 12450736139983 is 38993163705421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12450736139983 - 213 = 12450736131791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12450736134983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117459774853 + ... + 117459774958.
It is an arithmetic number, because the mean of its divisors is an integer number (3171413922462).
It is a 1-persistent number, because it is pandigital, but 2⋅12450736139983 = 24901472279966 is not.
Almost surely, 212450736139983 is an apocalyptic number.
12450736139983 is a deficient number, since it is larger than the sum of its proper divisors (234919549865).
12450736139983 is an equidigital number, since it uses as much as digits as its factorization.
12450736139983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234919549864.
The product of its (nonzero) digits is 29393280, while the sum is 61.
The spelling of 12450736139983 in words is "twelve trillion, four hundred fifty billion, seven hundred thirty-six million, one hundred thirty-nine thousand, nine hundred eighty-three".
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