Base | Representation |
---|---|
bin | 11100010100010110111011… |
… | …100011110100001001111011 |
3 | 121022222022122100011220222212 |
4 | 130110112323203310021323 |
5 | 112311013223213111141 |
6 | 1120514511232205335 |
7 | 35143013121635414 |
oct | 3424267343641173 |
9 | 538868570156885 |
10 | 124544313410171 |
11 | 36757a46069206 |
12 | 11b7563269984b |
13 | 546562ac5ba25 |
14 | 22a7d969b880b |
15 | e5ea3b75d2eb |
hex | 7145bb8f427b |
124544313410171 has 2 divisors, whose sum is σ = 124544313410172. Its totient is φ = 124544313410170.
The previous prime is 124544313410057. The next prime is 124544313410227. The reversal of 124544313410171 is 171014313445421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124544313410171 - 230 = 124543239668347 is a prime.
It is a super-3 number, since 3×1245443134101713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (124544313410971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62272156705085 + 62272156705086.
It is an arithmetic number, because the mean of its divisors is an integer number (62272156705086).
Almost surely, 2124544313410171 is an apocalyptic number.
124544313410171 is a deficient number, since it is larger than the sum of its proper divisors (1).
124544313410171 is an equidigital number, since it uses as much as digits as its factorization.
124544313410171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 41.
Adding to 124544313410171 its reverse (171014313445421), we get a palindrome (295558626855592).
The spelling of 124544313410171 in words is "one hundred twenty-four trillion, five hundred forty-four billion, three hundred thirteen million, four hundred ten thousand, one hundred seventy-one".
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