Base | Representation |
---|---|
bin | 10010000111111110010… |
… | …101010000000010110111 |
3 | 11102001212220120021222101 |
4 | 102013332111100002313 |
5 | 130401302202012101 |
6 | 2352103000042531 |
7 | 155661650562106 |
oct | 22077625200267 |
9 | 4361786507871 |
10 | 1245512532151 |
11 | 440245399128 |
12 | 18147b763447 |
13 | 905b374b1c4 |
14 | 443d6c9203d |
15 | 225ea61a401 |
hex | 121fe5500b7 |
1245512532151 has 4 divisors (see below), whose sum is σ = 1258352867632. Its totient is φ = 1232672196672.
The previous prime is 1245512532107. The next prime is 1245512532281. The reversal of 1245512532151 is 1512352155421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1245512532151 - 215 = 1245512499383 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1245512532151.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1245512533151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6420167595 + ... + 6420167788.
It is an arithmetic number, because the mean of its divisors is an integer number (314588216908).
Almost surely, 21245512532151 is an apocalyptic number.
1245512532151 is a deficient number, since it is larger than the sum of its proper divisors (12840335481).
1245512532151 is an equidigital number, since it uses as much as digits as its factorization.
1245512532151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12840335480.
The product of its digits is 60000, while the sum is 37.
Adding to 1245512532151 its reverse (1512352155421), we get a palindrome (2757864687572).
The spelling of 1245512532151 in words is "one trillion, two hundred forty-five billion, five hundred twelve million, five hundred thirty-two thousand, one hundred fifty-one".
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