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12457913443 is a prime number
BaseRepresentation
bin10111001101000110…
…01010110001100011
31012011012202120111121
423212203022301203
5201003211212233
65420104153111
7620501342233
oct134643126143
935135676447
1012457913443
115313192838
1224b8168797
131236ca2421
14862779cc3
154cda7392d
hex2e68cac63

12457913443 has 2 divisors, whose sum is σ = 12457913444. Its totient is φ = 12457913442.

The previous prime is 12457913437. The next prime is 12457913491. The reversal of 12457913443 is 34431975421.

12457913443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12457913443 - 25 = 12457913411 is a prime.

It is a super-2 number, since 2×124579134432 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12457913443.

It is not a weakly prime, because it can be changed into another prime (12457911443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6228956721 + 6228956722.

It is an arithmetic number, because the mean of its divisors is an integer number (6228956722).

Almost surely, 212457913443 is an apocalyptic number.

12457913443 is a deficient number, since it is larger than the sum of its proper divisors (1).

12457913443 is an equidigital number, since it uses as much as digits as its factorization.

12457913443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 362880, while the sum is 43.

The spelling of 12457913443 in words is "twelve billion, four hundred fifty-seven million, nine hundred thirteen thousand, four hundred forty-three".