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12493651969 is a prime number
BaseRepresentation
bin10111010001010111…
…00000000000000001
31012020201000021112201
423220223200000001
5201041333330334
65423422153201
7621414201211
oct135053400001
935221007481
1012493651969
115331382707
122508122801
131241506396
14867400241
154d1c82c14
hex2e8ae0001

12493651969 has 2 divisors, whose sum is σ = 12493651970. Its totient is φ = 12493651968.

The previous prime is 12493651931. The next prime is 12493651991. The reversal of 12493651969 is 96915639421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10834311744 + 1659340225 = 104088^2 + 40735^2 .

It is an emirp because it is prime and its reverse (96915639421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12493651969 - 225 = 12460097537 is a prime.

It is a super-2 number, since 2×124936519692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12493651909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6246825984 + 6246825985.

It is an arithmetic number, because the mean of its divisors is an integer number (6246825985).

It is a Proth number, since it is equal to 95319 ⋅ 217 + 1 and 95319 < 217.

Almost surely, 212493651969 is an apocalyptic number.

It is an amenable number.

12493651969 is a deficient number, since it is larger than the sum of its proper divisors (1).

12493651969 is an equidigital number, since it uses as much as digits as its factorization.

12493651969 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3149280, while the sum is 55.

The spelling of 12493651969 in words is "twelve billion, four hundred ninety-three million, six hundred fifty-one thousand, nine hundred sixty-nine".