12493811952073 has 2 divisors, whose sum is σ = 12493811952074. Its totient is φ = 12493811952072.

The previous prime is 12493811951987. The next prime is 12493811952077. The reversal of 12493811952073 is 37025911839421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8704104873984 + 3789707078089 = 2950272^2 + 1946717^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12493811952073 is a prime.

It is not a weakly prime, because it can be changed into another prime (12493811952077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6246905976036 + 6246905976037.

It is an arithmetic number, because the mean of its divisors is an integer number (6246905976037).

Almost surely, 2^{12493811952073} is an apocalyptic number.

It is an amenable number.

12493811952073 is a deficient number, since it is larger than the sum of its proper divisors (1).

12493811952073 is an equidigital number, since it uses as much as digits as its factorization.

12493811952073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 12493811952073 in words is "twelve trillion, four hundred ninety-three billion, eight hundred eleven million, nine hundred fifty-two thousand, seventy-three".