Base | Representation |
---|---|
bin | 100101010000001… |
… | …1011010000000011 |
3 | 10020010010022010122 |
4 | 1022200123100003 |
5 | 10030000423321 |
6 | 324012050455 |
7 | 42655642205 |
oct | 11240332003 |
9 | 3203108118 |
10 | 1250014211 |
11 | 5916671a6 |
12 | 2aa763a2b |
13 | 16bc861a4 |
14 | bc02c775 |
15 | 74b198ab |
hex | 4a81b403 |
1250014211 has 2 divisors, whose sum is σ = 1250014212. Its totient is φ = 1250014210.
The previous prime is 1250014177. The next prime is 1250014219. The reversal of 1250014211 is 1124100521.
It is a strong prime.
It is an emirp because it is prime and its reverse (1124100521) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1250014211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1250014211.
It is not a weakly prime, because it can be changed into another prime (1250014219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625007105 + 625007106.
It is an arithmetic number, because the mean of its divisors is an integer number (625007106).
Almost surely, 21250014211 is an apocalyptic number.
1250014211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250014211 is an equidigital number, since it uses as much as digits as its factorization.
1250014211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
The square root of 1250014211 is about 35355.5400326455. The cubic root of 1250014211 is about 1077.2214272233.
Adding to 1250014211 its reverse (1124100521), we get a palindrome (2374114732).
The spelling of 1250014211 in words is "one billion, two hundred fifty million, fourteen thousand, two hundred eleven".
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