12500214017 has 2 divisors, whose sum is σ = 12500214018. Its totient is φ = 12500214016.

The previous prime is 12500213959. The next prime is 12500214031. The reversal of 12500214017 is 71041200521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8961272896 + 3538941121 = 94664^2 + 59489^2 .

It is a cyclic number.

It is not a de Polignac number, because 12500214017 - 2¹² = 12500209921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12500213983 and 12500214001.

It is not a weakly prime, because it can be changed into another prime (12500210017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250107008 + 6250107009.

It is an arithmetic number, because the mean of its divisors is an integer number (6250107009).

Almost surely, 2^12500214017 is an apocalyptic number.

It is an amenable number.

12500214017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12500214017 is an equidigital number, since it uses as much as digits as its factorization.

12500214017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 23.

Adding to 12500214017 its reverse (71041200521), we get a palindrome (83541414538).

The spelling of 12500214017 in words is "twelve billion, five hundred million, two hundred fourteen thousand, seventeen".